VTF (dooley)

import math
import numpy as np
import matplotlib.pyplot as plt

#vtf = 5.05*math.exp(-0.138 * math.pi*300/180 * u ) * ( 1 - math.exp(-0.1 * math.pi * 300/180 * u) )

u = np.linspace(0, 10, 101)

#print(u)
#print(u.size)

vtf = np.empty(u.size)
for i in range(u.size):
    vtf[i] = 5.05*math.exp(-0.138*math.pi*300/180*u[i])*(1-math.exp(-0.1*math.pi*300/180*u[i]))

#print(vtf)

plt.plot(u, vtf)
plt.show()